Wisconsin dominates 'America's drunkest cities', Appleton tops list - Outbreak News Today | Outbreak News Today Outbreak News Today
Subscribe: RSS Twitter

In a recent CBS News report, which took data from a Robert Wood Johnson Foundation and University of Wisconsin Population Health Institute joint program, called County Health Rankings & Roadmaps and compiled the top 20 “drunkest cities” in the US. What was found was that Wisconsin accounted for 60 percent of the top 20.

Image/Debora Cartagena

Image/Debora Cartagena

The report notes that the number one drunkest city is Appleton, WI, which has a estimated population of 74,000 (2015), is the metropolitan area with the ninth highest concentration of bars in America. 26.8 percent of adults there report drinking in excess. 30.3 percent of the area’s driving deaths involve alcohol in some capacity. And 257 deaths out of 100,000 occur prematurely before the age of 75.

Appleton is not alone in the Badger state in this not so desirable list–it is joined by Oshkosh-Neenah (2), Green Bay (3), Madison (4), La Crosse – Onalaska (6), Fond du Lac (7), Eau Claire (9), Wausau (11), Sheboygan (12), Racine (15), Janesville-Beloit (16) and not-so-surprisingly,  Milwaukee-Waukesha-West Allis (17).

Most other metropolitan areas on the top 20 list are also out of the midwest to include Iowa City, Lincoln, NE and Fargo.

Related: 

1 Comment

Leave a Reply

© 2016 Outbreak News Today · Subscribe: RSS Twitter ·